Getting the Table of contents for a xml using xsl

Here is a typical example to create a Table of Contents for a given particular xml


XML:


<?xml version="1.0" encoding="UTF-8"?>

<main title="Main Heading">
<section title="Heading1">
<section title="Heading1.1" >
<section title="Heading1.1.1"></section>
<section title="Heading1.1.2"></section>
</section>
<section title="Heading2" >
<section title="Heading2.1"></section>
<section title="Heading2.2"></section>
</section>
</section>
</main>

Output:

Main Heading
1)Heading1
1.1)Heading1.1
1.1.1)Heading1.1.1
1.1.1)Heading1.1.2
2)Heading2
2.1)Heading2.1
2.2)Heading2.2


Answer is here

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" />

<xsl:template match="/main">
<xsl:value-of select="@title"/>
<xsl:text>
</xsl:text>
<xsl:call-template name="p">
<xsl:with-param name="prefix" select="''" />
<xsl:with-param name="indent" select="' '" />
</xsl:call-template>
</xsl:template>

<xsl:template name="p" >
<xsl:param name="prefix" />
<xsl:param name="indent" />
<xsl:for-each select="section" >
<xsl:value-of select="$indent"/>
<xsl:value-of select="$prefix"/>
<xsl:value-of select="position()"/>) <xsl:value-of select="@title" />
<xsl:text>
</xsl:text>
<xsl:call-template name="p">
<xsl:with-param name="prefix" select="concat($prefix, position(), '.')" />
<xsl:with-param name="indent" select="concat($indent, ' ')" />
</xsl:call-template>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>